$A$ force $\vec F = 5\hat i + 6\hat j - 4\hat k$ acting on a body produces a displacement $\vec s = 6\hat i + 5\hat k$. The work done by the force is $......$ units.

$A$ body of mass $5\, kg$ is placed at the origin and can move only on the $x$-axis. $A$ force of $10\, N$ is acting on it in a direction making an angle of $60^\circ$ with the $x$-axis and displaces it along the $x$-axis by $4\, m$. The work done by the force is $...\, J$.

$A$ body,acted upon by a force of $50 \, N$,is displaced through a distance of $10 \, m$ in a direction making an angle of $60^\circ$ with the force. The work done by the force is .......... $J$.

$A$ $1\text{ kg}$ block subjected to two simultaneous forces $\vec{F}_1 = (2\hat{i} + 3\hat{j} + 4\hat{k})\text{ N}$ and $\vec{F}_2 = (3\hat{i} - \hat{j} - 2\hat{k})\text{ N}$ is moved a distance of $25\text{ m}$ along the $(3\hat{i} - 4\hat{j})$ direction. The work done in this process is . . . . . . $J$.

$A$ particle moves from the origin in three segments of equal distance $d$: first along the $x$-axis,second parallel to the $y$-axis,and third parallel to the $z$-axis. $A$ constant force of magnitude $F = 50 \, N$ acts on the particle,always in the direction of motion. The work done by this force in each of the three segments is equal,and the total work done is $300 \, J$. What are the final coordinates of the particle?

$A$ force $\overrightarrow F = (5\hat i + 4\hat j) \ N$ acts on a body and produces a displacement $\overrightarrow S = (6\hat i - 5\hat j + 3\hat k) \ m$. The work done will be $J$.