A force of 200, N is applied at one end of a | vedclass

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(D) The thermal stress developed in a wire when its expansion is prevented is given by $\sigma = Y \alpha \Delta 	heta$.Since stress $\sigma = \frac{

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$8.8$

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(D) The thermal stress developed in a wire when its expansion is prevented is given by $\sigma = Y \alpha \Delta 	heta$.Since stress $\sigma = \frac{F}{A}$,the increase in tension $\Delta F$ is given by $\Delta F = YA \alpha \Delta 	heta$.Given:$Y = 2.2 	imes 10^{11}\, N/m^2$$A = 10^{-2}\, cm^2 = 10^{-2} 	imes 10^{-4}\, m^2 = 10^{-6}\, m^2$$\alpha = 8 	imes 10^{-6}\, ^\circ C^{-1}$$\Delta 	heta = 5\, ^\circ C$Substituting these values:$\Delta F = (2.2 	imes 10^{11}) 	imes (10^{-6}) 	imes (8 	imes 10^{-6}) 	imes 5$$\Delta F = 2.2 	imes 8 	imes 5 	imes 10^{11-6-6}$$\Delta F = 88 	imes 10^{-1} = 8.8\, N$.

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