A force of 6,N and another of 8,N can be appl | vedclass

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(B) The resultant force $R$ of two forces $F_1$ and $F_2$ acting at an angle $	heta$ is given by $R = \sqrt{F_1^2 + F_2^2 + 2F_1F_2 \cos 	heta}$.For

Vedclass · Accepted Answer

$11$

Vedclass · Answer

(B) The resultant force $R$ of two forces $F_1$ and $F_2$ acting at an angle $	heta$ is given by $R = \sqrt{F_1^2 + F_2^2 + 2F_1F_2 \cos 	heta}$.For two forces of $6\,N$ and $8\,N$,the maximum resultant is $F_1 + F_2 = 6 + 8 = 14\,N$ (when $	heta = 0^\circ$).The minimum resultant is $|F_1 - F_2| = |6 - 8| = 2\,N$ (when $	heta = 180^\circ$).Therefore,the resultant force must lie in the range $[2\,N, 14\,N]$.Among the given options,only $11\,N$ lies within this range.Thus,the correct option is $B$.

$A$ force of $6\,N$ and another of $8\,N$ can be applied together to produce the effect of a single force of $..........\,N$

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