A galvanometer has 30 divisions and a sensiti | vedclass

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(A) The full-scale deflection current $i_g$ of the galvanometer is given by:$i_g = 	ext{number of divisions} 	imes 	ext{sensitivity}$$i_g = 30 	im

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Resistance nearly $6\,k\Omega$ in series

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(A) The full-scale deflection current $i_g$ of the galvanometer is given by:$i_g = 	ext{number of divisions} 	imes 	ext{sensitivity}$$i_g = 30 	imes 16 	imes 10^{-6} \, A = 480 	imes 10^{-6} \, A = 4.8 	imes 10^{-4} \, A$To convert a galvanometer into a voltmeter,a high resistance $R$ is connected in series with it.The formula for the total resistance is:$V = i_g(R + G)$Assuming the internal resistance $G$ of the galvanometer is negligible compared to the high series resistance $R$ (or considering $R+G \approx R$):$R \approx \frac{V}{i_g} = \frac{3}{4.8 	imes 10^{-4}} = \frac{30000}{4.8} = 6250 \, \Omega = 6.25 \, k\Omega$Thus,a resistance of nearly $6 \, k\Omega$ connected in series is required.

$A$ galvanometer has $30$ divisions and a sensitivity of $16\,\mu A/\text{div}$. It can be converted into a voltmeter to read $3\,V$ by connecting:

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