A galvanometer of 50 , Omega resistance has 2 | vedclass

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(D) The full-scale deflection current $I_g$ is calculated by multiplying the number of divisions by the current per division: $I_g = 25 	imes 4 	ime

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$2450 \, \Omega$ in series

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(D) The full-scale deflection current $I_g$ is calculated by multiplying the number of divisions by the current per division: $I_g = 25 	imes 4 	imes 10^{-4} \, A = 100 	imes 10^{-4} \, A = 0.01 \, A$. To convert a galvanometer into a voltmeter, a high resistance $R$ must be connected in series with it. The formula for the series resistance is $R = \frac{V}{I_g} - G$, where $V = 25 \, V$, $I_g = 0.01 \, A$, and $G = 50 \, \Omega$. Substituting the values: $R = \frac{25}{0.01} - 50 = 2500 - 50 = 2450 \, \Omega$. Therefore, a resistance of $2450 \, \Omega$ should be connected in series.

$A$ galvanometer of $50 \, \Omega$ resistance has $25$ divisions. $A$ current of $4 \times 10^{-4} \, A$ gives a deflection of one division. To convert this galvanometer into a voltmeter having a range of $25 \, V$, it should be connected with a resistance of

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