A gas decolourises Bayer's reagent but does n | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) Bayer's reagent $(1\% 	ext{ alkaline } KMnO_4 	ext{ solution})$ is used to detect the presence of unsaturation (double or triple bonds) in organ

Vedclass · Accepted Answer

Ethene

Vedclass · Answer

(A) Bayer's reagent $(1\% 	ext{ alkaline } KMnO_4 	ext{ solution})$ is used to detect the presence of unsaturation (double or triple bonds) in organic compounds. Both alkenes and alkynes decolourise it.Tollen's reagent (ammoniacal silver nitrate) reacts only with terminal alkynes (alkynes having a hydrogen atom attached to a triply bonded carbon) to form a white precipitate of silver acetylide.$1.$ Ethene $(CH_2=CH_2)$ is an alkene. It decolourises Bayer's reagent due to the presence of a double bond but does not react with Tollen's reagent because it is not a terminal alkyne.$2.$ Ethyne $(CH \equiv CH)$ is a terminal alkyne. It decolourises Bayer's reagent and also reacts with Tollen's reagent.$3.$ Ethane and Methane are saturated hydrocarbons (alkanes) and do not react with either reagent.Therefore,the gas that decolourises Bayer's reagent but does not react with Tollen's reagent is Ethene.

$A$ gas decolourises Bayer's reagent but does not react with Tollen's reagent. This gas is:

Similar Questions

Assertion : $1$-Butene on reaction with $HBr$ in the presence of a peroxide produces $1$-bromobutane.
Reason : It involves the formation of a primary radical.

Which of the following reagents is used to convert propene to propan-$1$-ol?

What is Baeyer's reagent?

Major product of the given reaction is $CH_2=CH-CH_2-I \xrightarrow[CCl_4]{HI(excess)}$

In the given reaction sequence,identify the final product $C$:
$CH_2=CH-CH=CH_2$ $\xrightarrow{HCl, 40^{\circ}C} A$ $\xrightarrow{HI} C$
(Note: The reaction proceeds via electrophilic addition to a conjugated diene.)

Vedclass Test Series

Exam Paper Generator

Online Exam Module