A gas diffuses 1/3 times as fast as hydrogen. | vedclass

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(B) According to Graham's law of diffusion,the rate of diffusion $r$ is inversely proportional to the square root of the molar mass $M$: $r \propto \f

Vedclass · Accepted Answer

$18$

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(B) According to Graham's law of diffusion,the rate of diffusion $r$ is inversely proportional to the square root of the molar mass $M$: $r \propto \frac{1}{\sqrt{M}}$.Thus,$\frac{r_g}{r_H} = \sqrt{\frac{M_H}{M_g}}$.Given that the rate of the gas is $1/3$ times that of hydrogen $(H_2)$,where $M_H = 2 \ g/mol$,we have $\frac{1}{3} = \sqrt{\frac{2}{M_g}}$.Squaring both sides: $\frac{1}{9} = \frac{2}{M_g}$.Therefore,$M_g = 18 \ g/mol$.

$A$ gas diffuses $1/3$ times as fast as hydrogen. Its molecular weight is

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