(C) Since the temperature $T$ and volume $V$ of the vessel remain constant,we use the ideal gas law $PV = nRT$.From this,$n = \frac{PV}{RT}$. Since $V

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

$20\%$ of the gas escaped due to the leakage

(C) Since the temperature $T$ and volume $V$ of the vessel remain constant,we use the ideal gas law $PV = nRT$.From this,$n = \frac{PV}{RT}$. Since $V, R,$ and $T$ are constant,$n \propto P$.Initial state: $P_1 = 5 \text{ atm}$,$n_1 = n$.Final state: $P_2 = 4 \text{ atm}$,$n_2 = n'$.Therefore,$\frac{n'}{n} = \frac{P_2}{P_1} = \frac{4}{5} = 0.8$.This means $n' = 0.8n$.The amount of gas that escaped is $\Delta n = n - n' = n - 0.8n = 0.2n$.Percentage of gas escaped = $\frac{0.2n}{n} \times 100\% = 20\%$.

Class 11 Physics Kinetic Theory of Gases Gas Laws (Charles, Boyle's, Avagadro's, Gay Lussacs and Dalton's law) and Ideal gas Equation

Medium

$A$ gas is enclosed in a vessel at a constant temperature at a pressure of $5 \text{ atm}$ and volume $4 \text{ L}$. Due to a leakage in the vessel,after some time,the pressure is reduced to $4 \text{ atm}$. As a result,the:

A
volume of the gas decreased by $20\%$
B
average $K.E.$ of gas molecule decreases by $20\%$
C
$20\%$ of the gas escaped due to the leakage
D
$25\%$ of the gas escaped due to the leakage

Explore More

Browse All

Question Bank

All Subjects

Class 11 Questions

Class 11

Physics Questions

Chapter

Kinetic Theory of Gases

Subtopic

Gas Laws (Charles, Boyle's, Avagadro's, Gay Lussacs and Dalton's law) and Ideal gas Equation

The pressure $Vs$ temperature graph of an ideal gas is shown in the figure. If the density of the gas at point $A$ is $\rho _0$,what will be the density at point $B$?

Medium

View Solution

The graph of four gases with the same number of moles is given. Then:

Difficult

View Solution

One mole of a perfect gas in a cylinder fitted with a piston has a pressure $P,$ volume $V,$ and temperature $T.$ If the temperature is increased by $1 \, K$ keeping pressure constant,the increase in volume is

Medium

View Solution

The relationship between pressure and the density of a gas expressed by Boyle's law,$P = K\rho$,holds true:

Easy

View Solution

$A$ vessel of volume $8 \, L$ contains an ideal gas at $300 \, K$ and $2 \, atm$ pressure. The gas is allowed to leak until the pressure becomes $125 \, kPa$. Calculate the number of moles that leaked out if the temperature remains constant.

Difficult

View Solution

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial

For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free

For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo

$A$ gas is enclosed in a vessel at a constant temperature at a pressure of $5 \text{ atm}$ and volume $4 \text{ L}$. Due to a leakage in the vessel,after some time,the pressure is reduced to $4 \text{ atm}$. As a result,the:

Similar Questions

The pressure $Vs$ temperature graph of an ideal gas is shown in the figure. If the density of the gas at point $A$ is $\rho _0$,what will be the density at point $B$?

The graph of four gases with the same number of moles is given. Then:

One mole of a perfect gas in a cylinder fitted with a piston has a pressure $P,$ volume $V,$ and temperature $T.$ If the temperature is increased by $1 \, K$ keeping pressure constant,the increase in volume is

The relationship between pressure and the density of a gas expressed by Boyle's law,$P = K\rho$,holds true:

$A$ vessel of volume $8 \, L$ contains an ideal gas at $300 \, K$ and $2 \, atm$ pressure. The gas is allowed to leak until the pressure becomes $125 \, kPa$. Calculate the number of moles that leaked out if the temperature remains constant.

Vedclass Test Series

Exam Paper Generator

Online Exam Module