A girl running a race accelerates at 2.5 , m | vedclass

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(B) Given: Initial velocity $u = 0 \, m/s$,acceleration $a = 2.5 \, m s^{-2}$,and time $t = 4 \, s$.To find the distance traveled $(S)$,we use the sec

Vedclass · Accepted Answer

$20$

Vedclass · Answer

(B) Given: Initial velocity $u = 0 \, m/s$,acceleration $a = 2.5 \, m s^{-2}$,and time $t = 4 \, s$.To find the distance traveled $(S)$,we use the second equation of motion:$S = ut + \frac{1}{2}at^2$Substituting the given values into the equation:$S = (0 	imes 4) + \frac{1}{2} 	imes 2.5 	imes (4)^2$$S = 0 + 0.5 	imes 2.5 	imes 16$$S = 1.25 	imes 16 = 20 \, m$Therefore,the girl travels $20 \, m$ in this time.

$A$ girl running a race accelerates at $2.5 \, m s^{-2}$ for the first $4 \, s$ of the race. How far does she travel in this time (in $, m$)?

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