A heavy nucleus is unstable for any value of | vedclass

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Question

(A) The correct option is $A$.In heavy nuclei,the number of protons is very large. Since protons are positively charged,they exert a strong electrosta

Vedclass · Accepted Answer

Electrostatic repulsion dominates over nuclear attraction

Vedclass · Answer

(A) The correct option is $A$.In heavy nuclei,the number of protons is very large. Since protons are positively charged,they exert a strong electrostatic repulsive force on each other.While the strong nuclear force is attractive,it is a short-range force that only acts between nearest neighbors.As the size of the nucleus increases,the long-range electrostatic repulsion between all protons grows faster than the short-range nuclear attraction,eventually making the nucleus unstable.

$A$ heavy nucleus is unstable for any value of $\frac{N}{P}$ because

Similar Questions

Which of the following figures represents the variation of $\ln \left(\frac{R}{R_{0}}\right)$ with $\ln A$ (where $R =$ radius of a nucleus and $A =$ its mass number)?

Consider the following two statements, $A$ and $B$ and identify the correct answer given below:
$A$. Nuclear density is same for all nuclei.
$B$. Radius of the nucleus $R$ and its mass number $A$ are related as $\sqrt{A} \propto R^{1 / 6}$.

Calculate the height of the potential barrier for a head-on collision of two deuterons. (Radius of deuteron is $2$ fm).

What is the particle $x$ in the following nuclear reaction :
${ }_4^9 Be+{ }_2^4 He \rightarrow{ }_6^{12} C+x$

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