$A$ helium nucleus makes a full rotation in a circle of radius $0.8 \ m$ in $2 \ s$. The value of the magnetic field $B$ at the centre of the circle will be

  • A
    $\frac{10^{-19}}{\mu_0}$
  • B
    $10^{-19} \mu_0$
  • C
    $2 \times 10^{-10} \mu_0$
  • D
    $\frac{2 \times 10^{-10}}{\mu_0}$

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