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(A) Given: Horizontal force,$F = 10\, N$ and coefficient of friction between the block and the wall,$\mu = 0.2$.For the block to remain stationary aga

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$2$

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(A) Given: Horizontal force,$F = 10\, N$ and coefficient of friction between the block and the wall,$\mu = 0.2$.For the block to remain stationary against the wall,the horizontal force $F$ provides the normal reaction $R$ on the block.Therefore,$R = F = 10\, N$.The frictional force $f$ acting upwards balances the weight $W$ of the block acting downwards.Thus,$W = f = \mu R$.Substituting the values,$W = 0.2 	imes 10 = 2\, N$.Hence,the weight of the block is $2\, N$.

$A$ horizontal force of $10\, N$ is necessary to just hold a block stationary against a wall. The coefficient of friction between the block and the wall is $0.2$. The weight of the block is ........ $N$.

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