A horizontal straight wire 20, m long extendi | vedclass

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(B) Given:Length of the wire,$\ell = 20\, m$Speed of the wire,$v = 5.0\, m/s$Horizontal component of Earth's magnetic field,$B_H = 0.30 	imes 10^{-4}

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$3$

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(B) Given:Length of the wire,$\ell = 20\, m$Speed of the wire,$v = 5.0\, m/s$Horizontal component of Earth's magnetic field,$B_H = 0.30 	imes 10^{-4}\, Wb/m^2$The motional $e.m.f.$ induced in a conductor moving in a magnetic field is given by the formula:$e = B_H v \ell$Substituting the given values:$e = (0.30 	imes 10^{-4}) 	imes 5.0 	imes 20$$e = 0.30 	imes 10^{-4} 	imes 100$$e = 0.30 	imes 10^{-2}\, V$$e = 3 	imes 10^{-3}\, V$Since $1\, mV = 10^{-3}\, V$,the induced $e.m.f.$ is:$e = 3\, mV$

$A$ horizontal straight wire $20\, m$ long extending from east to west is falling with a speed of $5.0\, m/s$,at right angles to the horizontal component of the earth's magnetic field $0.30 \times 10^{-4}\, Wb/m^2$. The instantaneous value of the $e.m.f.$ induced in the wire will be.....$mV$.

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