A hydrogen atom in its ground state absorbs 1 | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The energy of the ground state of a hydrogen atom is $E_1 = -13.6 \ eV$. When it absorbs $10.2 \ eV$ of energy,its new energy becomes $E = -13.6 \

Vedclass · Accepted Answer

$1.05 	imes 10^{-34} \ J \cdot s$

Vedclass · Answer

(A) The energy of the ground state of a hydrogen atom is $E_1 = -13.6 \ eV$. When it absorbs $10.2 \ eV$ of energy,its new energy becomes $E = -13.6 \ eV + 10.2 \ eV = -3.4 \ eV$. This corresponds to the first excited state,where the principal quantum number $n = 2$. The orbital angular momentum $L$ of an electron in a hydrogen atom is given by $L = \frac{nh}{2\pi}$. In the ground state $(n_1 = 1)$,the angular momentum is $L_1 = \frac{1 \cdot h}{2\pi}$. In the first excited state $(n_2 = 2)$,the angular momentum is $L_2 = \frac{2 \cdot h}{2\pi} = \frac{h}{\pi}$. The increase in orbital angular momentum is $\Delta L = L_2 - L_1 = \frac{2h}{2\pi} - \frac{h}{2\pi} = \frac{h}{2\pi}$. Substituting the value of $h = 6.6 	imes 10^{-34} \ J \cdot s$: $\Delta L = \frac{6.6 	imes 10^{-34}}{2 	imes 3.14} \approx \frac{6.6 	imes 10^{-34}}{6.28} \approx 1.05 	imes 10^{-34} \ J \cdot s$.

$A$ hydrogen atom in its ground state absorbs $10.2 \ eV$ of energy. The orbital angular momentum is increased by (Given Planck constant $h = 6.6 \times 10^{-34} \ J \cdot s$)

Similar Questions

The ground state energy of a hydrogen atom is $-13.6 \text{ eV}$. The potential energy of the electron in this state is: (in $\text{ eV}$)

In the following atoms and molecules,for the transition from $n = 2$ to $n = 1$,the spectral line of minimum wavelength will be produced by:

In Bohr's model,if the atomic radius of the first orbit is ${r_0}$,then the radius of the fourth orbit is

According to de-Broglie,the de-Broglie wavelength for an electron in an orbit of radius $5.3 \times 10^{-11} \ m$ of a hydrogen atom is $10^{-10} \ m$. The principal quantum number for this electron is:

The orbital frequency of an electron in the hydrogen atom is proportional to

Vedclass Test Series

Exam Paper Generator

Online Exam Module