A jar contains 10 red marbles and 30 green on | vedclass

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(C) Let the number of red marbles to be added be $x$.Initially,the number of red marbles is $10$ and green marbles is $30$,so the total number of marb

Vedclass · Accepted Answer

$35$

Vedclass · Answer

(C) Let the number of red marbles to be added be $x$.Initially,the number of red marbles is $10$ and green marbles is $30$,so the total number of marbles is $10 + 30 = 40$.After adding $x$ red marbles,the new number of red marbles becomes $10 + x$ and the new total number of marbles becomes $40 + x$.According to the problem,the percentage of red marbles should be $60 \%$.Therefore,$\frac{10+x}{40+x} = \frac{60}{100}$.Simplifying the fraction,$\frac{10+x}{40+x} = \frac{3}{5}$.Cross-multiplying gives $5(10 + x) = 3(40 + x)$.$50 + 5x = 120 + 3x$.$5x - 3x = 120 - 50$.$2x = 70$.$x = 35$.Thus,$35$ red marbles must be added.

$A$ jar contains $10$ red marbles and $30$ green ones. How many red marbles must be added to the jar so that $60 \%$ of the marbles will be red?

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