(A) From the figure,it is clear that liquid $1$ floats on liquid $2$. Since the lighter liquid floats over the heavier liquid,we can conclude that $\r

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(A) From the figure,it is clear that liquid $1$ floats on liquid $2$. Since the lighter liquid floats over the heavier liquid,we can conclude that $\rho_1 The ball is in equilibrium at the interface of the two liquids. For an object to float in a liquid,its density must be less than the density of the liquid. Since the ball is partially submerged in liquid $1$ and partially in liquid $2$,its density $\rho_3$ must be greater than the density of the upper liquid $(\rho_1)$ and less than the density of the lower liquid $(\rho_2)$. Therefore,the condition for equilibrium is $\rho_1 < \rho_3 < \rho_2$.

Class 11 Physics Fluid Mechanics and Surface Tension Buoyancy, Archimedes' Principle and Laws of Floatation

Medium

$A$ jar is filled with two non-mixing liquids $1$ and $2$ having densities $\rho_1$ and $\rho_2$ respectively. $A$ solid ball,made of a material of density $\rho_3$,is dropped in the jar. It comes to equilibrium in the position shown in the figure. Which of the following is true for $\rho_1, \rho_2$ and $\rho_3$?

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A
$\rho_1 < \rho_3 < \rho_2$
B
$\rho_3 < \rho_1 < \rho_2$
C
$\rho_1 > \rho_3 > \rho_2$
D
$\rho_1 < \rho_2 < \rho_3$

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Class 11 Questions

Class 11

Physics Questions

Chapter

Fluid Mechanics and Surface Tension

Subtopic

Buoyancy, Archimedes' Principle and Laws of Floatation

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Two rods of the same material and length have their electric resistance in the ratio $1:2$. When both rods are dipped in water,the correct statement will be:

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$A$ hollow cone floats with its axis vertical up to one-third of its height in a liquid of relative density $0.8$ and with its vertex submerged. When another liquid of relative density $\rho$ is filled in it up to one-third of its height,the cone floats up to half its vertical height. The height of the cone is $0.10 \ m$ and the radius of the circular base is $0.05 \ m$. The specific gravity $\rho$ is given by

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$A$ hemispherical bowl just floats without sinking in a liquid of density $1.2 \times 10^3 \ kg/m^3$. If the outer diameter and the density of the bowl are $1 \ m$ and $2 \times 10^4 \ kg/m^3$ respectively,then the inner diameter of the bowl will be........ $m$.

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Two rods of the same material and length have their electric resistance in the ratio $1:2$. When both rods are dipped in water,the correct statement will be:

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