A jet of liquid of cross-sectional area a str | vedclass

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(A) The mass of liquid striking the wall per unit time is given by $\frac{dm}{dt} = A \cdot v \cdot \rho$,where $A$ is the cross-sectional area,$v$ is

Vedclass · Accepted Answer

$2av^2ho \sin 	heta$

Vedclass · Answer

(A) The mass of liquid striking the wall per unit time is given by $\frac{dm}{dt} = A \cdot v \cdot ho$,where $A$ is the cross-sectional area,$v$ is the velocity,and $ho$ is the density.Since the jet makes an angle $	heta$ with the wall,the component of velocity normal to the wall is $v_n = v \sin 	heta$.The liquid rebounds elastically,meaning the normal component of velocity changes from $v \sin 	heta$ to $-v \sin 	heta$.The change in momentum per unit time (force) exerted by the wall on the liquid is $F = \frac{dp}{dt} = \frac{dm}{dt} \cdot \Delta v_n$.$F = (avho) \cdot (v \sin 	heta - (-v \sin 	heta)) = (avho) \cdot (2v \sin 	heta) = 2av^2ho \sin 	heta$.By Newton's third law,the force exerted by the liquid on the wall is equal in magnitude,so the normal force is $2av^2ho \sin 	heta$.

$A$ jet of liquid of cross-sectional area $a$ strikes a wall making an angle $\theta$ with the wall. The liquid strikes the wall with velocity $v$ and rebounds elastically. If the density of the liquid is $\rho$,the normal force on the wall is:

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