A light ray incident normally on a plane mirr | vedclass

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Question

(C) When a light ray is incident normally (perpendicularly) on a plane mirror, the angle of incidence $(i)$ is $0^{\circ}$.According to the law of ref

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$180^{\circ}$

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(C) When a light ray is incident normally (perpendicularly) on a plane mirror, the angle of incidence $(i)$ is $0^{\circ}$.According to the law of reflection, the angle of reflection $(r)$ is also $0^{\circ}$.The light ray reflects back along the same path.The deviation $(\delta)$ produced by a mirror is given by the formula $\delta = 180^{\circ} - 2i$.Substituting $i = 0^{\circ}$, we get $\delta = 180^{\circ} - 2(0^{\circ}) = 180^{\circ}$.Therefore, the light ray suffers a deviation of $180^{\circ}$.

$A$ light ray incident normally on a plane mirror suffers a deviation of

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