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(B) The acceleration $a$ of a system of two masses $m_1$ and $m_2$ connected by a string over a pulley is given by $a = \left(\frac{m_1 - m_2}{m_1 + m

Vedclass · Accepted Answer

$9: 7$

Vedclass · Answer

(B) The acceleration $a$ of a system of two masses $m_1$ and $m_2$ connected by a string over a pulley is given by $a = \left(\frac{m_1 - m_2}{m_1 + m_2}\right) g$,assuming $m_1 > m_2$. Given $a = \frac{g}{8}$,we have: $\frac{g}{8} = \left(\frac{m_1 - m_2}{m_1 + m_2}\right) g$ $\frac{1}{8} = \frac{m_1 - m_2}{m_1 + m_2}$ $m_1 + m_2 = 8m_1 - 8m_2$ $9m_2 = 7m_1$ $\frac{m_1}{m_2} = \frac{9}{7}$ Thus,the ratio of the masses is $9:7$.

$A$ light string passing over a smooth light pulley connects two blocks of masses $m_1$ and $m_2$ (vertically). If the acceleration of the system is $g / 8$,then the ratio of the masses $m_1 : m_2$ is

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