$A$ loop $ABCDEFA$ of straight edges has six corner points $A(0,0,0), B(5,0,0), C(5,5,0), D(0,5,0), E(0,5,5)$ and $F(0,0,5)$. The magnetic field in this region is $\overrightarrow{B}=(3 \hat{i}+4 \hat{k}) \; T$. The quantity of magnetic flux through the loop $ABCDEFA$ (in $\text{Wb}$) is:

Write Gauss's law for magnetism.

$A$ long straight wire carrying a constant current $i$ is placed in the same plane as a rectangular loop of length $l$. The distance of the sides of the loop from the wire are $r_1$ and $r_2$. If the area under the curve of the magnetic field $B$ versus distance $r$ graph between $r_1$ and $r_2$ is $A$,find the magnetic flux through the loop.

$A$ loop,made of straight edges,has four corners at $A(L, L, 0)$,$B(-L, L, 0)$,$C(-L, -L, 0)$,and $D(L, -L, 0)$. $A$ magnetic field $\vec B = B_0(\hat i + \hat k) \text{ T}$ is present in the region. The magnetic flux passing through the loop $ABCD$ is:

The figure represents an area $A = 0.5\,m^2$ situated in a uniform magnetic field $B = 2.0\,Wb/m^2$. The area makes an angle of $60^o$ with the magnetic field. The value of the magnetic flux through the area is equal to......$Wb$.

Which of the following conclusions can be drawn from the result $\oint \vec{B} \cdot d\vec{A} = 0$?