A luminous object is placed 20 , cm from the | vedclass

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(B) For the convex mirror,the object distance $u = -20 \, cm$ and focal length $f = +5 \, cm$.Using the mirror formula $\frac{1}{f} = \frac{1}{v} + \f

Vedclass · Accepted Answer

$12$

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(B) For the convex mirror,the object distance $u = -20 \, cm$ and focal length $f = +5 \, cm$.Using the mirror formula $\frac{1}{f} = \frac{1}{v} + \frac{1}{u}$,we get $\frac{1}{5} = \frac{1}{v} - \frac{1}{20}$.Solving for $v$,we find $\frac{1}{v} = \frac{1}{5} + \frac{1}{20} = \frac{4+1}{20} = \frac{5}{20} = \frac{1}{4}$,so $v = +4 \, cm$.The image formed by the convex mirror is $4 \, cm$ behind the mirror.The distance of the object from the convex mirror is $20 \, cm$ in front of it.The total distance between the object and the image formed by the convex mirror is $20 \, cm + 4 \, cm = 24 \, cm$.For the plane mirror to form an image that coincides with the image from the convex mirror,the plane mirror must be placed exactly halfway between the object and the image formed by the convex mirror.Therefore,the distance of the plane mirror from the object is $\frac{24 \, cm}{2} = 12 \, cm$.

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