A man can row 9 text{ km/hr} in still water. | vedclass

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(B) Let the distance be $d 	ext{ km}$.Speed of the man in still water $u = 9 	ext{ km/hr}$.Speed of the stream $v = 3 	ext{ km/hr}$.Speed downstrea

Vedclass · Accepted Answer

$36$

Vedclass · Answer

(B) Let the distance be $d 	ext{ km}$.Speed of the man in still water $u = 9 	ext{ km/hr}$.Speed of the stream $v = 3 	ext{ km/hr}$.Speed downstream $= u + v = 9 + 3 = 12 	ext{ km/hr}$.Speed upstream $= u - v = 9 - 3 = 6 	ext{ km/hr}$.Time taken to travel downstream $t_1 = \frac{d}{12} 	ext{ hours}$.Time taken to travel upstream $t_2 = \frac{d}{6} 	ext{ hours}$.According to the problem,$t_2 = t_1 + 3$.$\frac{d}{6} = \frac{d}{12} + 3$.Multiply by $12$ to clear the denominators: $2d = d + 36$.$d = 36 	ext{ km}$.

$A$ man can row $9 \text{ km/hr}$ in still water. If the river is running at $3 \text{ km/hr}$,it takes $3 \text{ hours}$ more to row upstream than to row downstream for the same distance. How far is the place? (in $\text{km}$)

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