A man with a wrist watch and a pendulum clock | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The correct answer is $D$.The functioning of a wrist watch depends on the spring action (mechanical tension),so it is not affected by gravity.Howe

Vedclass · Accepted Answer

The pendulum clock will stop,but the wrist watch will function normally.

Vedclass · Answer

(D) The correct answer is $D$.The functioning of a wrist watch depends on the spring action (mechanical tension),so it is not affected by gravity.However,the time period of a pendulum clock is given by $T = 2\pi \sqrt{\frac{l}{g_{eff}}}$.During free fall,the effective acceleration due to gravity $(g_{eff})$ becomes zero.Substituting $g_{eff} = 0$ into the formula,we get $T = 2\pi \sqrt{\frac{l}{0}} = \infty$.Since the time period becomes infinite,the pendulum clock stops functioning during the fall.

$A$ man with a wrist watch and a pendulum clock rises to the top of a $TV$ tower. Both the wrist watch and the pendulum clock accidentally fall from the top of the tower. Then:

Similar Questions

$A$ simple pendulum of length $L$ is suspended from the roof of a trolley. The trolley moves in a horizontal direction with an acceleration $a$. What would be the period of oscillation of the simple pendulum? [$g$ is the acceleration due to gravity]

$A$ simple pendulum is vibrating in an evacuated chamber. It will oscillate with:

The force constant of an oscillating simple pendulum is

$A$ pendulum is executing simple harmonic motion and its maximum kinetic energy is $K_1$. If the length of the pendulum is doubled and it performs simple harmonic motion with the same angular amplitude as in the first case,its maximum kinetic energy is $K_2$,then:

Vedclass Test Series

Exam Paper Generator

Online Exam Module