A man is standing on a balance and his weight | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The weight of a person is defined as the force exerted by gravity on the person,which is given by $W = mg$. When a person stands on a balance,the

Vedclass · Accepted Answer

Remains same

Vedclass · Answer

(C) The weight of a person is defined as the force exerted by gravity on the person,which is given by $W = mg$. When a person stands on a balance,the balance measures the normal force exerted by the person on the scale. As long as the person is standing on the balance and not accelerating vertically,the normal force is equal to the weight of the person. Taking a step to the left side while remaining on the balance does not change the total mass of the person or the gravitational force acting on them. Therefore,the reading on the balance remains the same.

$A$ man is standing on a balance and his weight is measured. If he takes a step to the left side,then his weight:

Similar Questions

The equation of the plane passing through $(1, 1, 1)$ and $(1, -1, -1)$ and perpendicular to $2x - y + z + 5 = 0$ is:

Name the ion responsible for unmasking of active sites for myosin for cross-bridge activity during muscle contraction.

When a spring is stretched by $2 \ cm$,it stores $100 \ J$ of energy. If it is further stretched by $2 \ cm$,the stored energy will be increased by $.... \ J$.

If $\alpha, \beta, \gamma$ are the roots of $x^3+2x^2-3x-1=0$,then $\alpha^{-2}+\beta^{-2}+\gamma^{-2}=$

The radius of gyration of a uniform thin rod of length $L$ about an axis passing normally through its centre of mass is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module