A man sells an article at 5 % above its cost | vedclass

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Question

(A) Let the cost price $(CP)$ be $x$.Initial selling price $(SP_1)$ $= x + 0.05x = 1.05x = \frac{21x}{20}$.New cost price $(CP_2)$ $= x - 0.05x = 0.95

Vedclass · Accepted Answer

$400$

Vedclass · Answer

(A) Let the cost price $(CP)$ be $x$.Initial selling price $(SP_1)$ $= x + 0.05x = 1.05x = \frac{21x}{20}$.New cost price $(CP_2)$ $= x - 0.05x = 0.95x = \frac{19x}{20}$.New selling price $(SP_2)$ $= CP_2 + 10\% 	ext{ of } CP_2 = 1.10 	imes \frac{19x}{20} = \frac{1.10 	imes 19x}{20} = \frac{20.9x}{20} = \frac{209x}{200}$.According to the problem,the difference between the two selling prices is $Rs. 2$:$SP_1 - SP_2 = 2$$\frac{21x}{20} - \frac{209x}{200} = 2$Multiply by $200$ to clear the denominator:$210x - 209x = 400$$x = 400$.Therefore,the cost price of the article is $Rs. 400$.

$A$ man sells an article at $5 \%$ above its cost price. If he had bought it at $5 \%$ less than what he had paid for it and sold it at $Rs. 2$ less,he would have gained $10 \%$. The cost price of the article is (in $Rs.$)

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