A man suffering from short-sightedness (myopi | vedclass

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(D) person suffering from short-sightedness (myopia) cannot see distant objects clearly. To correct this,a concave lens is used to bring the image of

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$-0.5$

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(D) person suffering from short-sightedness (myopia) cannot see distant objects clearly. To correct this,a concave lens is used to bring the image of distant objects (at infinity) to the person's far point $(2\,m)$.Using the lens formula: $\frac{1}{f} = \frac{1}{v} - \frac{1}{u}$.Here,$v = -2\,m$ (the far point) and $u = -\infty$.$\frac{1}{f} = \frac{1}{-2} - \frac{1}{-\infty} = -0.5\,m^{-1}$.Power $P = \frac{1}{f(m)} = -0.5\,D$.

$A$ man suffering from short-sightedness (myopia) is unable to see objects distinctly at a distance greater than $2\,m$. The power of the lens required to correct this defect should be.......$D$

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