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(B) Let $W$ be the time taken to walk one way and $R$ be the time taken to ride one way.Given: $W + R = 6$ hours $30$ minutes $= 390$ minutes $... (i)

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$520$

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(B) Let $W$ be the time taken to walk one way and $R$ be the time taken to ride one way.Given: $W + R = 6$ hours $30$ minutes $= 390$ minutes $... (i)$If he rides both ways,he gains $2$ hours $10$ minutes compared to walking and riding. This means the time taken to ride both ways is $2R = (W + R) - 2$ hours $10$ minutes.$2R = 6$ hours $30$ minutes $- 2$ hours $10$ minutes $= 4$ hours $20$ minutes $= 260$ minutes $... (ii)$From $(ii)$,$R = 130$ minutes.Substitute $R$ in $(i)$: $W + 130 = 390 \Rightarrow W = 260$ minutes.The time taken to walk both ways is $2W = 2 	imes 260 = 520$ minutes.

$A$ man takes $6$ hours $30$ minutes in walking to a certain place and riding back. He would have gained $2$ hours $10$ minutes by riding both ways. How long would he take to walk both ways? (in minutes)

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