A man with blood group B marries a woman with | vedclass

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(C) The blood group of the father is $B$ and the mother is $A$. For the child to have blood group $B$,the father must be heterozygous $(I^B I^O)$ and

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$I^B I^O$

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(C) The blood group of the father is $B$ and the mother is $A$. For the child to have blood group $B$,the father must be heterozygous $(I^B I^O)$ and the mother must be heterozygous $(I^A I^O)$.According to the Punnett square:- Father's gametes: $I^B, I^O$- Mother's gametes: $I^A, I^O$- Possible genotypes of children: $I^A I^B$ $(AB)$,$I^A I^O$ $(A)$,$I^B I^O$ $(B)$,$I^O I^O$ $(O)$.Since the child has blood group $B$,the genotype must be $I^B I^O$.

$A$ man with blood group $B$ marries a woman with blood group $A$ and their first child has blood group $B$. What is the genotype of the child?

Similar Questions

In humans,the $ABO$ blood group is controlled by the $I$ gene. It has three alleles: $I^A$,$I^B$,and $i$. Although there are three different alleles,six different genotypes are possible. How many phenotypes are observed in this case?

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$A$ man with blood group $A$ marries a woman having blood group $B$. The maximum possible blood groups among their progenies are

Which of the following is an excellent example of multiple alleles?

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