A mass m is supported by a massless string wo | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) For the falling mass $m$,the equation of motion is: $mg - T = ma$  ... $(1)$For the rotation of the hollow cylinder,the torque $	au$ is given by

Vedclass · Accepted Answer

$\frac{g}{2}$

Vedclass · Answer

(D) For the falling mass $m$,the equation of motion is: $mg - T = ma$  ... $(1)$For the rotation of the hollow cylinder,the torque $	au$ is given by $	au = I\alpha$. Since the cylinder is hollow,its moment of inertia is $I = mR^2$.The torque is provided by the tension $T$,so $T \cdot R = I\alpha = (mR^2) \cdot \frac{a}{R}$,where $a = R\alpha$ is the linear acceleration of the string.This simplifies to $T = ma$ ... $(2)$Substituting equation $(2)$ into equation $(1)$:$mg - ma = ma$$mg = 2ma$$a = \frac{g}{2}$

$A$ mass $m$ is supported by a massless string wound around a uniform hollow cylinder of mass $m$ and radius $R$. If the string does not slip on the cylinder,with what acceleration will the mass fall on release?

Similar Questions

$A$ coordination complex contains $Co^{3+}$,$Cl^{-}$,and $NH_3$. When dissolved in water,one mole of this complex gives a total of $3$ moles of ions. The complex is

Identify the figure with its correct function.

The equation $\sqrt{3} \sin x + \cos x = 4$ has

When $AgNO_3$ is heated strongly,the products formed are

The $IUPAC$ name for the complex $[Co(NO_2)(NH_3)_5]Cl_2$ is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module