$A$ mass of $10\,kg$ is suspended vertically by a rope from the roof. When a horizontal force is applied on the rope at some point,the rope deviates at an angle of $45^o$ from the vertical. If the suspended mass is at equilibrium,the magnitude of the force applied is .......... $N$ $(g = 10\,ms^{-2})$.

  • A
    $200$
  • B
    $140$
  • C
    $70$
  • D
    $100$

Explore More

Similar Questions

$A$ body of mass $m$ is suspended by two strings making angles $\theta_1$ and $\theta_2$ with the horizontal ceiling with tensions $T_1$ and $T_2$ respectively. If $T_1 = \sqrt{3} T_2$,then the angles $\theta_1$ and $\theta_2$ are:

$A$ body is in equilibrium under the action of three coplanar forces $P, Q$ and $R$ as shown in the figure. Select the correct statement.

Describe the different types of common forces.

What will be the tension produced in the string $PQ$ for the given system?

$A$ light rod acted upon by three forces is in equilibrium. Which of the following diagrams shows the possible position and direction of the forces?

Difficult
View Solution

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo