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(C) Let the selling price of each house be $SP = Rs. 1.995$ Lakhs.For the first house,gain is $20 \%$. So,Cost Price $CP_1 = \frac{SP}{1 + 20/100} = \

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$4 \%$ loss

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(C) Let the selling price of each house be $SP = Rs. 1.995$ Lakhs.For the first house,gain is $20 \%$. So,Cost Price $CP_1 = \frac{SP}{1 + 20/100} = \frac{1.995}{1.2} = Rs. 1.6625$ Lakhs.For the second house,loss is $20 \%$. So,Cost Price $CP_2 = \frac{SP}{1 - 20/100} = \frac{1.995}{0.8} = Rs. 2.49375$ Lakhs.Total Cost Price $CP = CP_1 + CP_2 = 1.6625 + 2.49375 = Rs. 4.15625$ Lakhs.Total Selling Price $SP_{total} = 1.995 + 1.995 = Rs. 3.99$ Lakhs.Since $CP > SP_{total}$,there is a loss.Loss $= CP - SP_{total} = 4.15625 - 3.99 = 0.16625$ Lakhs.Loss $\% = \left( \frac{	ext{Loss}}{CP} ight) 	imes 100 = \left( \frac{0.16625}{4.15625} ight) 	imes 100 = 4 \%$.Alternatively,when two items are sold at the same price with $x \%$ gain and $x \%$ loss,the overall result is always a loss of $\left( \frac{x}{10} ight)^2 \% = \left( \frac{20}{10} ight)^2 \% = 4 \%$ loss.

$A$ man sells two houses at the rate of $Rs. 1.995$ Lakhs each. On one house he gains $20 \%$ and on the other he loses $20 \%$. His gain or loss per cent in the whole transaction is

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