A metal M on heating in nitrogen gas gives Y. | vedclass

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Question

(C) The reaction of metal $M$ (specifically $Mg$) with nitrogen gas is: $3Mg + N_2 	o Mg_3N_2$ $(Y)$.$Mg_3N_2$ $(Y)$ reacts with water to produce amm

Vedclass · Accepted Answer

$Mg_3N_2$

Vedclass · Answer

(C) The reaction of metal $M$ (specifically $Mg$) with nitrogen gas is: $3Mg + N_2 	o Mg_3N_2$ $(Y)$.$Mg_3N_2$ $(Y)$ reacts with water to produce ammonia gas: $Mg_3N_2 + 6H_2O 	o 3Mg(OH)_2 + 2NH_3 \uparrow$ (colourless gas).When $NH_3$ is passed through $CuSO_4$ solution,it forms a deep blue complex: $CuSO_4 + 4NH_3 	o [Cu(NH_3)_4]SO_4$ (Blue complex).Therefore,$Y$ is $Mg_3N_2$.

$A$ metal $M$ on heating in nitrogen gas gives $Y$. $Y$ on treatment with $H_2O$ gives a colourless gas which when passed through $CuSO_4$ solution gives a blue colour. $Y$ is

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