$A$ metal $(X)$ dissolves in both dilute $HCl$ and dilute $NaOH$ to liberate $H_2$ gas. Addition of $NH_4Cl$ and excess $NH_4OH$ to an $HCl$ solution of $(X)$ produces $(Y)$ as a precipitate. $(Y)$ is also produced by adding $NH_4Cl$ to the $NaOH$ solution of $(X)$. The species $(X)$ and $(Y)$,respectively,are:

• A
  $Zn$ and $Zn(OH)_2$
• B
  $Al$ and $Al(OH)_3$
• C
  $Zn$ and $Na_2ZnO_2$
• D
  $Al$ and $NaAlO_2$