A metal nitrate reacts with KI to give a blac | vedclass

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(B) The reaction of bismuth nitrate with potassium iodide $(KI)$ produces a black precipitate of bismuth$(III)$ iodide $(BiI_3)$.$Bi(NO_3)_3(aq) + 3KI

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$Bi^{3+}$

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(B) The reaction of bismuth nitrate with potassium iodide $(KI)$ produces a black precipitate of bismuth$(III)$ iodide $(BiI_3)$.$Bi(NO_3)_3(aq) + 3KI(aq) \xrightarrow{\quad} BiI_3(s) + 3KNO_3(aq)$Upon adding an excess of $KI$,the black precipitate dissolves to form a soluble complex,potassium tetraiodobismuthate$(III)$,which is orange in color.$BiI_3(s) + KI(aq) \xrightarrow{\quad} K[BiI_4](aq)$Thus,the cation is $Bi^{3+}$.

$A$ metal nitrate reacts with $KI$ to give a black precipitate which on addition of excess of $KI$ converts into an orange-colored solution. The cation of the metal nitrate is

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