A metal obtained directly by roasting of its | vedclass

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Question

(C) The correct answer is $(C)$.When cinnabar $(HgS)$ ore is roasted in the presence of air,it undergoes self-reduction to form mercury metal:$HgS + O

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$Hg$

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(C) The correct answer is $(C)$.When cinnabar $(HgS)$ ore is roasted in the presence of air,it undergoes self-reduction to form mercury metal:$HgS + O_2 \xrightarrow{\Delta} Hg + SO_2$At the roasting temperature $(773 - 873 \ K)$,mercury exists as a vapor. These vapors are then condensed to obtain liquid mercury,which is approximately $99.7 \%$ pure.

$A$ metal obtained directly by roasting of its sulphide ore is

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