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(B) When a charge $Q$ is placed at the centre of the spherical cavity of a metallic shell,an equal and opposite charge $-Q$ is induced on the inner su

Vedclass · Accepted Answer

$-\frac{Q}{4\pi R_1^2}$

Vedclass · Answer

(B) When a charge $Q$ is placed at the centre of the spherical cavity of a metallic shell,an equal and opposite charge $-Q$ is induced on the inner surface of the shell to ensure that the electric field inside the conducting material is zero.The surface charge density $\sigma$ is defined as the charge per unit area.For the inner surface,the charge is $-Q$ and the surface area is $4\pi R_1^2$.Therefore,the surface charge density on the inner surface is $\sigma_1 = \frac{	ext{Charge}}{	ext{Area}} = \frac{-Q}{4\pi R_1^2}$.

$A$ metallic spherical shell has an inner radius $R_1$ and outer radius $R_2$. $A$ charge $Q$ is placed at the centre of the spherical cavity. What will be the surface charge density on the inner surface?

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