A mixture of chlorides of Cu, Cd, Cr and Fe w | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) $1$. When $H_2S$ gas is passed through the acidified solution,$Cu^{2+}$ and $Cd^{2+}$ ions precipitate as $CuS$ and $CdS$ (Group $II$ cations). Th

Vedclass · Accepted Answer

Sodium and chromium ion

Vedclass · Answer

(C) $1$. When $H_2S$ gas is passed through the acidified solution,$Cu^{2+}$ and $Cd^{2+}$ ions precipitate as $CuS$ and $CdS$ (Group $II$ cations). The filtrate contains $Cr^{3+}$ and $Fe^{3+}$.$2$. Boiling with $HNO_3$ ensures $Fe^{2+}$ is oxidized to $Fe^{3+}$.$3$. Upon adding $NH_4Cl$ and excess $NaOH$ (or $NH_4OH$),$Fe^{3+}$ precipitates as $Fe(OH)_3$ (brown precipitate).$4$. $Cr^{3+}$ reacts with excess $NaOH$ to form a soluble complex,$[Cr(OH)_4]^-$,which remains in the filtrate.$5$. Therefore,the filtrate contains $Cr^{3+}$ ions and $Na^+$ ions (from the added $NaOH$). Thus,the filtrate gives a test for sodium and chromium ions.

$A$ mixture of chlorides of $Cu, Cd, Cr$ and $Fe$ was dissolved in water acidified with dil. $HCl$ and $H_2S$ gas was passed. It was filtered,and boiled later adding two drops of $HNO_3$. To this solution $NH_4Cl$ and $NH_4OH$ (or $NaOH$ in excess) were added. The filtrate shall give a test for :-

Similar Questions

The ion that cannot be precipitated by both $HCl$ and $H_2S$ is

Which compound gives a black color with $NH_4OH$?

In which of the following is lead sulfate $(PbSO_4)$ soluble?

Among $Fe^{3+}$, $Pb^{2+}$, $Cu^{2+}$, and $Mn^{2+}$, identify the one that gets precipitated out while passing $H_2S$ gas in the presence of $NH_4OH$ as a group reagent. The highest possible oxidation state of the corresponding metal is:

Which of the following pairs cannot be separated by passing $H_2S$ gas?

Vedclass Test Series

Exam Paper Generator

Online Exam Module