$A$ motor bike running at $5\, m s^{-1}$,picks up a velocity of $30\, m s^{-1}$ in $5\, s$. Calculate $(i)$ acceleration $(ii)$ distance covered during acceleration.

(N/A) Given: Initial velocity $u = 5\, m s^{-1}$,Final velocity $v = 30\, m s^{-1}$,Time $t = 5\, s$.
$(i)$ To calculate acceleration $(a)$: Using the first equation of motion,$v = u + at$.
$30 = 5 + a \times 5$
$30 - 5 = 5a$
$25 = 5a$
$a = 5\, m s^{-2}$.
$(ii)$ To calculate distance covered $(S)$: Using the third equation of motion,$v^2 - u^2 = 2aS$.
$(30)^2 - (5)^2 = 2 \times 5 \times S$
$900 - 25 = 10S$
$875 = 10S$
$S = 87.5\, m$.