(B) Total distance covered $= 20 \text{ km} + 29 \text{ km} = 49 \text{ km}$.Total time taken $= 30 \text{ min} + 40 \text{ min} = 70 \text{ min}$.To

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(B) Total distance covered $= 20 \text{ km} + 29 \text{ km} = 49 \text{ km}$.Total time taken $= 30 \text{ min} + 40 \text{ min} = 70 \text{ min}$.To convert time into hours,divide by $60$: $70 \text{ min} = \frac{70}{60} \text{ hr} = \frac{7}{6} \text{ hr}$.Average speed $= \frac{\text{Total distance}}{\text{Total time}} = \frac{49}{7/6} \text{ km/hr}$.Average speed $= 49 \times \frac{6}{7} = 7 \times 6 = 42 \text{ km/hr}$.

Competitive Quantitative Aptitude Average Average

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$A$ motorist covered the first $20 \text{ km}$ of his journey in $30 \text{ minutes}$ and the remaining $29 \text{ km}$ in $40 \text{ minutes}$. His average speed in $\text{km/hr}$ is:

A
$41 \frac{3}{4}$
B
$42$
C
$49$
D
$57 \frac{1}{6}$

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$A$ student was asked to find the arithmetic mean of the numbers $3, 11, 7, 9, 15, 13, 8, 19, 17, 21, 14$ and $x$. He found the mean to be $12$. What should be the number in place of $x$?

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$A$ motorist covered the first $20 \text{ km}$ of his journey in $30 \text{ minutes}$ and the remaining $29 \text{ km}$ in $40 \text{ minutes}$. His average speed in $\text{km/hr}$ is:

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$A$ student was asked to find the arithmetic mean of the numbers $3, 11, 7, 9, 15, 13, 8, 19, 17, 21, 14$ and $x$. He found the mean to be $12$. What should be the number in place of $x$?

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