A mouse jumps off from the 15th floor of a hi | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) Given,distance of landing from the building,$s = 12 \, m$.Height of each floor,$h = 3 \, m$.Total height of the building,$H = 15 	imes 3 = 45 \,

Vedclass · Accepted Answer

$15$

Vedclass · Answer

(D) Given,distance of landing from the building,$s = 12 \, m$.Height of each floor,$h = 3 \, m$.Total height of the building,$H = 15 	imes 3 = 45 \, m$.Using the second equation of motion for vertical motion under gravity (with initial vertical velocity $u_y = 0$):$H = u_y t + \frac{1}{2} g t^2$$45 = 0 + \frac{1}{2} 	imes 10 	imes t^2$$45 = 5 t^2$$t^2 = 9 \Rightarrow t = 3 \, s$.Now,for horizontal motion with constant speed $v$:$s = v 	imes t$$12 = v 	imes 3$$v = 4 \, m/s$.To convert $m/s$ to $km/h$,multiply by $\frac{18}{5}$:$v = 4 	imes \frac{18}{5} = \frac{72}{5} = 14.4 \, km/h$.Rounding to the nearest integer,the speed is $15 \, km/h$.

$A$ mouse jumps off from the $15$th floor of a high-rise building and lands $12 \, m$ from the building. Assume that each floor is of $3 \, m$ height. The horizontal speed with which the mouse jumps is closest to ............... $km/h$.

Similar Questions

$A$ projectile is fired at an angle of $45^{\circ}$ with the horizontal. The elevation angle of the projectile at its highest point as seen from the point of projection is:

Two bodies are projected with the same velocity. If one is projected at an angle of $30^\circ$ and the other at an angle of $60^\circ$ to the horizontal,the ratio of the maximum heights reached is

The trajectory of a projectile,projected from the ground,is given by $y = x - \frac{x^2}{20}$,where $x$ and $y$ are measured in meters. The maximum height attained by the projectile will be $...........\,m$.

$A$ projectile is projected from the ground with an initial velocity $\vec{u} = u_0 \hat{i} + v_0 \hat{j}$. If the acceleration due to gravity $g$ is along the negative $y$-direction,find the maximum displacement in the $x$-direction (horizontal range).

$A$ particle is projected with velocity $2 \sqrt{gh}$,so that it just flies over two walls of equal height $h$ and $2h$ distance apart from each other. Find the time for which the particle flies between the walls.

Vedclass Test Series

Exam Paper Generator

Online Exam Module