A neutral water molecule (H_2O) in its vapor | vedclass

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Question

(C) neutral water molecule $(H_2O)$ contains $10$ electrons and $10$ protons. The total charge $q$ of the positive or negative center is $10e$,where $

Vedclass · Accepted Answer

$4 \ pm$

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(C) neutral water molecule $(H_2O)$ contains $10$ electrons and $10$ protons. The total charge $q$ of the positive or negative center is $10e$,where $e = 1.6 	imes 10^{-19} \ C$.The electric dipole moment is given by $p = q \cdot d$,where $d$ is the distance between the centers of positive and negative charge.Given $p = 6.4 	imes 10^{-30} \ C \cdot m$ and $q = 10 	imes 1.6 	imes 10^{-19} \ C = 1.6 	imes 10^{-18} \ C$.Therefore,$d = \frac{p}{q} = \frac{6.4 	imes 10^{-30}}{1.6 	imes 10^{-18}} \ m = 4 	imes 10^{-12} \ m$.Since $1 \ pm = 10^{-12} \ m$,the distance is $4 \ pm$.

$A$ neutral water molecule $(H_2O)$ in its vapor state has an electric dipole moment of magnitude $6.4 \times 10^{-30} \ C \cdot m$. How far apart are the molecule's centers of positive and negative charge?

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