A non-uniformly shaped conductor is charged. | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) For a charged conductor in electrostatic equilibrium,the entire conductor is an equipotential surface,meaning the electric potential is the same a

Vedclass · Accepted Answer

Electric field will be maximum

Vedclass · Answer

(B) For a charged conductor in electrostatic equilibrium,the entire conductor is an equipotential surface,meaning the electric potential is the same at every point. However,the surface charge density $\sigma$ is inversely proportional to the radius of curvature $R$ $(\sigma \propto 1/R)$. At the sharpest point,the radius of curvature is minimum,which makes the surface charge density maximum. Since the electric field near the surface is given by $E = \sigma / \epsilon_0$,the electric field is also maximum at the sharpest point.

$A$ non-uniformly shaped conductor is charged. Then,at its sharpest point:

Similar Questions

If volume charge density is $\rho$,then what will be the charge on $\Delta V$ volume?

If a solid and a hollow conducting sphere have the same radius, then:

Write an equation for the electric potential due to a linear charge distribution.

Explain linear charge density,surface charge density,and volume charge density for uniform charge distribution.

Obtain the formula for the electric field due to a long thin wire of uniform linear charge density $\lambda$ without using Gauss's law.

Vedclass Test Series

Exam Paper Generator

Online Exam Module