A nucleus ^{A}_{Z} X has mass represented by | vedclass

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Question

(A) The binding energy $(B.E.)$ of a nucleus is the energy equivalent of the mass defect $(\Delta m)$.The mass defect is defined as the difference bet

Vedclass · Accepted Answer

$B.E. = [Z M_p + (A - Z) M_n - M(A, Z)] c^2$

Vedclass · Answer

(A) The binding energy $(B.E.)$ of a nucleus is the energy equivalent of the mass defect $(\Delta m)$.The mass defect is defined as the difference between the sum of the masses of individual nucleons (protons and neutrons) and the actual mass of the nucleus.Number of protons = $Z$Number of neutrons = $A - Z$Mass defect $\Delta m = [Z M_p + (A - Z) M_n - M(A, Z)]$According to Einstein's mass-energy equivalence principle, $B.E. = \Delta m c^2$.Therefore, $B.E. = [Z M_p + (A - Z) M_n - M(A, Z)] c^2$.

$A$ nucleus $^{A}_{Z} X$ has mass represented by $M(A, Z)$. If $M_p$ and $M_n$ denote the mass of a proton and a neutron respectively, and $B.E.$ is the binding energy in $MeV$, then:

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