A nucleus of atomic mass A and atomic number | vedclass

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(C) When a nucleus emits a $\beta^-$ particle (an electron,represented as $_{-1}e^0$),the atomic mass $A$ remains unchanged because the total number o

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$A, Z + 1$

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(C) When a nucleus emits a $\beta^-$ particle (an electron,represented as $_{-1}e^0$),the atomic mass $A$ remains unchanged because the total number of nucleons is conserved. However,a neutron is converted into a proton,which increases the atomic number $Z$ by $1$.The decay process is represented as:$_{Z}X^{A} ightarrow _{Z+1}Y^{A} + _{-1}e^{0} + \bar{
u}$Thus,the resulting nucleus has an atomic mass of $A$ and an atomic number of $Z + 1$.

$A$ nucleus of atomic mass $A$ and atomic number $Z$ emits a $\beta^-$ particle. The atomic mass and atomic number of the resulting nucleus are

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