A number is of two digits. The position of di | vedclass

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(D) Let the two-digit number be represented as $(10x + y)$,where $x$ is the tens digit and $y$ is the units digit.When the positions of the digits are

Vedclass · Accepted Answer

$11$

Vedclass · Answer

(D) Let the two-digit number be represented as $(10x + y)$,where $x$ is the tens digit and $y$ is the units digit.When the positions of the digits are interchanged,the new number becomes $(10y + x)$.Adding the original number and the new number,we get:$(10x + y) + (10y + x) = 11x + 11y$$= 11(x + y)$Since the sum is $11(x + y)$,the resultant number will always be divisible by $11$.

$A$ number is of two digits. The position of digits is interchanged and the new number is added to the original number. The resultant number will always be divisible by

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