A number when divided by 221 gives a remainde | vedclass

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Question

(C) Let the number be $N$. According to the problem,$N = 221q + 43$,where $q$ is the quotient.We want to find the remainder when $N$ is divided by $17

Vedclass · Accepted Answer

$9$

Vedclass · Answer

(C) Let the number be $N$. According to the problem,$N = 221q + 43$,where $q$ is the quotient.We want to find the remainder when $N$ is divided by $17$.$N = (13 	imes 17)q + 43$.Since $(13 	imes 17)q$ is perfectly divisible by $17$,the remainder depends only on dividing $43$ by $17$.$43 = 17 	imes 2 + 9$.Thus,the remainder is $9$.

$A$ number when divided by $221$ gives a remainder $43$. What remainder will be obtained by dividing the same number by $17$?

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