A painter is applying force himself to raise | vedclass

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(C) Let $m = 100\, kg$ be the mass of the painter and $M = 50\, kg$ be the mass of the box. Let $T$ be the tension in the rope and $R$ be the normal c

Vedclass · Accepted Answer

force of contact between the painter and the floor is $375\, N$

Vedclass · Answer

(C) Let $m = 100\, kg$ be the mass of the painter and $M = 50\, kg$ be the mass of the box. Let $T$ be the tension in the rope and $R$ be the normal contact force between the painter and the floor of the box.For the system (painter + box),the total upward force is $2T$ (since two segments of the rope pull the system up) and the total downward force is $(m + M)g$. The equation of motion is:$2T - (m + M)g = (m + M)a$$2T = (m + M)(g + a)$$2T = (100 + 50)(10 + 5) = 150 	imes 15 = 2250\, N$$T = 1125\, N$For the painter,the upward forces are $T$ (tension in the rope he is pulling) and $R$ (normal force from the floor). The downward force is $mg$. The equation of motion is:$T + R - mg = ma$$1125 + R - 100(10) = 100(5)$$1125 + R - 1000 = 500$$R = 500 - 125 = 375\, N$Thus,the tension in the rope is $1125\, N$ and the contact force is $375\, N$. Comparing with the given options,option $C$ is correct.

$A$ painter is applying force himself to raise him and the box with an acceleration of $5\, m/s^2$ by a massless rope and pulley arrangement as shown in the figure. The mass of the painter is $100\, kg$ and that of the box is $50\, kg$. If $g = 10\, m/s^2$,then:

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