$A$ parallel plate capacitor of capacitance $C$ is connected to a battery and charged to a potential difference $V$. Another capacitor of capacitance $2C$ is similarly charged to a potential difference $2V$. The charging batteries are then removed,and the capacitors are connected in parallel such that the positive terminal of one is connected to the negative terminal of the other. The final energy of the configuration is:

  • A
    Zero
  • B
    $\frac{3}{2} CV^2$
  • C
    $\frac{25}{6} CV^2$
  • D
    $\frac{9}{2} CV^2$

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