A paramagnetic substance in the form of a cub | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The volume of the cube is $V = (1\, cm)^3 = (10^{-2}\, m)^3 = 10^{-6}\, m^3$.The intensity of magnetization $I$ is defined as the magnetic dipole

Vedclass · Accepted Answer

$3.3 	imes 10^{-4}$

Vedclass · Answer

(D) The volume of the cube is $V = (1\, cm)^3 = (10^{-2}\, m)^3 = 10^{-6}\, m^3$.The intensity of magnetization $I$ is defined as the magnetic dipole moment per unit volume:$I = \frac{M}{V} = \frac{20 	imes 10^{-6}\, J/T}{10^{-6}\, m^3} = 20\, A/m$.The magnetic susceptibility $\chi$ is given by the ratio of the intensity of magnetization $I$ to the magnetic intensity $H$:$\chi = \frac{I}{H}$.Given $H = 60 	imes 10^3\, A/m$,we have:$\chi = \frac{20}{60 	imes 10^3} = \frac{1}{3} 	imes 10^{-3} = 0.333 	imes 10^{-3} = 3.33 	imes 10^{-4}$.

$A$ paramagnetic substance in the form of a cube with sides $1\, cm$ has a magnetic dipole moment of $20 \times 10^{-6}\, J/T$ when a magnetic intensity of $60 \times 10^3\, A/m$ is applied. Its magnetic susceptibility is

Similar Questions

At a temperature of $30\,^oC$,the susceptibility of a ferromagnetic material is found to be $\chi$. Its susceptibility at $333\,^oC$ is....$\chi$.

The magnetic susceptibility of the material of a rod is $599$. The absolute permeability of the material of the rod will be $\left[\mu_0=4 \pi \times 10^{-7} \text{ SI unit}\right]$.

The $S.I.$ unit of magnetic permeability is

The relative permeability of iron is $2000$. Its absolute permeability in $SI$ units will be (given $\frac{\mu_0}{4 \pi} = 10^{-7} \text{ SI units}$):

The magnetic susceptibility of the material of a rod is $499$. Permeability of vacuum is $4 \pi \times 10^{-7} \ H/m$. The absolute permeability of the material of the rod in $H/m$ is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module