A particle carrying a charge equal to 100 tim | vedclass

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(B) The current $i$ produced by a rotating charge is given by $i = qf$,where $f$ is the frequency of rotation.Given $f = 1 	ext{ Hz}$ and $q = 100e =

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${10^{ - 17}}{\mu _0}$

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(B) The current $i$ produced by a rotating charge is given by $i = qf$,where $f$ is the frequency of rotation.Given $f = 1 	ext{ Hz}$ and $q = 100e = 100 	imes 1.6 	imes 10^{-19} 	ext{ C} = 1.6 	imes 10^{-17} 	ext{ C}$.Thus,$i = 1.6 	imes 10^{-17} 	ext{ A}$.The magnetic field at the centre of a circular loop is $B = \frac{\mu_0 i}{2r}$.Substituting the values: $B = \frac{\mu_0 	imes 1.6 	imes 10^{-17}}{2 	imes 0.8}$.$B = \frac{\mu_0 	imes 1.6 	imes 10^{-17}}{1.6} = 10^{-17} \mu_0 	ext{ T}$.

$A$ particle carrying a charge equal to $100$ times the charge on an electron is rotating per second in a circular path of radius $0.8 \ m$. The value of the magnetic field produced at the centre will be (where ${\mu _0}$ is the permeability of vacuum).

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